Problem Set 2
Stochastic Foundations for Finance
Instructions: This problem set is due on 11/5 at 11:59 pm Central Time and is an individual assignment. All problems must be handwritten. Write full sentences to answer questions that require an explanation. Scan your work and submit a PDF file.
Problem 1 The number of defaults X next year in a small portfolio of loans has the probability mass function p_{X}(0) = 0.5, p_{X}(1) = 0.3, and p_{X}(2) = 0.2.
- Write down the probability generating function G_{X}(z).
- Use G_{X} to compute \operatorname{E}(X) and \operatorname{V}(X).
- A second portfolio has a number of defaults Y that is independent of X and has the same distribution. Compute the probability generating function of X + Y and read off the probability mass function of the total number of defaults.
- Use your answer to the previous part to compute \operatorname{P}(X + Y \geq 3).
Problem 2 A trading strategy makes money on each day with probability p = 0.6, independently across days. Let W be the number of days needed to obtain three winning days.
- Explain why W = X_{1} + X_{2} + X_{3}, where X_{1}, X_{2}, and X_{3} are independent random variables with the geometric distribution of parameter p.
- Find the probability generating function of W.
- Use the probability generating function to compute \operatorname{E}(W) and \operatorname{V}(W).
- Compute \operatorname{P}(W = 3) and \operatorname{P}(W = 4).
Problem 3 The number of orders N that arrive at a market maker during a minute has a Poisson distribution with parameter \lambda = 20. Each order is independently for one lot with probability 1/2 and for two lots with probability 1/2, and is independent of N. Let S be the total number of lots ordered during the minute.
- Find the probability generating function of S.
- Use it to compute \operatorname{E}(S) and \operatorname{V}(S). Compare \operatorname{V}(S) with \operatorname{E}(S).
- A bank holds n = 1{,}000 independent loans, each with a default probability of 0.002 over the next year. Compute the exact probability of no defaults, and the probability of no defaults under the Poisson approximation.
- Compute the probability of at most two defaults, exactly and with the Poisson approximation.
Problem 4 Let Y = e^{X} where X = \mu + \sigma Z, \mu = 1, \sigma = 2, and Z \sim \mathcal{N}(0, 1). In addition, the daily log returns R_{1}, R_{2}, \ldots, R_{250} of a stock are independent and normally distributed with mean 0.0004 and standard deviation 0.01, and the annual log return is R = R_{1} + \cdots + R_{250}.
- Use the moment generating function of X to compute \operatorname{E}(Y^{0.5}) and \operatorname{E}(Y^{-1}).
- Use moment generating functions to find the distribution of R.
- Compute the probability that the stock loses money over the year, that is, \operatorname{P}(R < 0).
- Compute the expected gross return \operatorname{E}(e^{R}) over the year.
Problem 5 Let X_{1}, X_{2}, \ldots be independent random variables, each equal to +1 with probability p and to -1 with probability q = 1 - p, and let S_{n} = X_{1} + \cdots + X_{n} with S_{0} = 0.
- Compute the moment generating function M_{X}(\theta) and the cumulant generating function K_{X}(\theta) of X_{1}, and use K_{X} to find the mean and the variance of X_{1}.
- Find the value \theta^{*} \neq 0 such that K_{X}(\theta^{*}) = 0, and show that e^{\theta^{*}} = q / p.
- Let \mathcal{F}_{n} be the information set generated by X_{1}, \ldots, X_{n}. Use the properties of conditional expectation to show that \operatorname{E}\left((q / p)^{S_{n + 1}} \mid \mathcal{F}_{n}\right) = (q / p)^{S_{n}}.
- Now let p = q = 1/2. Show that the characteristic function of S_{n} / \sqrt{n} is \cos(u / \sqrt{n})^{n}, and compare its value at u = 1 for n = 10 and n = 100 with the characteristic function of a standard normal random variable. Which theorem does this illustrate?
Problem 6 A gambler bets $1 on each round of a game, wins each round with probability p, and loses it with probability q = 1 - p. The gambler starts with no winnings, S_{0} = 0, and stops as soon as the net winnings reach A or -B.
Use the ruin probability for a biased coin derived in the notes to complete the table below, which reports the probability of winning $100 before losing $100.
Chance of winning one round 0.500 0.495 0.490 0.480 0.470 Chance to win $100 Argue that, if your chance of winning each round is less than 0.5, it is much better to bet $100 at once than $1 at a time.
Let g(K) = \operatorname{E}(\tau \mid S_{0} = K) be the expected number of rounds until the game stops when the gambler starts at K. Explain why g(K) = 1 + p \, g(K + 1) + q \, g(K - 1), \qquad g(-B) = g(A) = 0.
Show that g(K) = K / (q - p) solves the equation in the previous part without the boundary conditions, and conclude that the general solution is g(K) = \frac{K}{q - p} + \alpha + \beta \left(\frac{q}{p}\right)^{K}.
A bet on red in American roulette wins with probability p = 18/38. Compute the expected duration g(0) of the game when A = B = 10, and compare it with the expected duration AB = 100 of a fair game.
Normal Distribution Table
The table below computes \Phi(z) = \operatorname{P}(Z \leq z) if Z \sim \mathcal{N}(0, 1) and z \geq 0. The rows denote the first decimal whereas the columns denote the second decimal. If you need \Phi(-z), you can always use \Phi(-z) = 1 - \Phi(z).
| z | 0.00 | 0.01 | 0.02 | 0.03 | 0.04 | 0.05 | 0.06 | 0.07 | 0.08 | 0.09 |
|---|---|---|---|---|---|---|---|---|---|---|
| 0.0 | 0.5000 | 0.5040 | 0.5080 | 0.5120 | 0.5160 | 0.5199 | 0.5239 | 0.5279 | 0.5319 | 0.5359 |
| 0.1 | 0.5398 | 0.5438 | 0.5478 | 0.5517 | 0.5557 | 0.5596 | 0.5636 | 0.5675 | 0.5714 | 0.5753 |
| 0.2 | 0.5793 | 0.5832 | 0.5871 | 0.5910 | 0.5948 | 0.5987 | 0.6026 | 0.6064 | 0.6103 | 0.6141 |
| 0.3 | 0.6179 | 0.6217 | 0.6255 | 0.6293 | 0.6331 | 0.6368 | 0.6406 | 0.6443 | 0.6480 | 0.6517 |
| 0.4 | 0.6554 | 0.6591 | 0.6628 | 0.6664 | 0.6700 | 0.6736 | 0.6772 | 0.6808 | 0.6844 | 0.6879 |
| 0.5 | 0.6915 | 0.6950 | 0.6985 | 0.7019 | 0.7054 | 0.7088 | 0.7123 | 0.7157 | 0.7190 | 0.7224 |
| 0.6 | 0.7257 | 0.7291 | 0.7324 | 0.7357 | 0.7389 | 0.7422 | 0.7454 | 0.7486 | 0.7517 | 0.7549 |
| 0.7 | 0.7580 | 0.7611 | 0.7642 | 0.7673 | 0.7704 | 0.7734 | 0.7764 | 0.7794 | 0.7823 | 0.7852 |
| 0.8 | 0.7881 | 0.7910 | 0.7939 | 0.7967 | 0.7995 | 0.8023 | 0.8051 | 0.8078 | 0.8106 | 0.8133 |
| 0.9 | 0.8159 | 0.8186 | 0.8212 | 0.8238 | 0.8264 | 0.8289 | 0.8315 | 0.8340 | 0.8365 | 0.8389 |
| 1.0 | 0.8413 | 0.8438 | 0.8461 | 0.8485 | 0.8508 | 0.8531 | 0.8554 | 0.8577 | 0.8599 | 0.8621 |
| 1.1 | 0.8643 | 0.8665 | 0.8686 | 0.8708 | 0.8729 | 0.8749 | 0.8770 | 0.8790 | 0.8810 | 0.8830 |
| 1.2 | 0.8849 | 0.8869 | 0.8888 | 0.8907 | 0.8925 | 0.8944 | 0.8962 | 0.8980 | 0.8997 | 0.9015 |
| 1.3 | 0.9032 | 0.9049 | 0.9066 | 0.9082 | 0.9099 | 0.9115 | 0.9131 | 0.9147 | 0.9162 | 0.9177 |
| 1.4 | 0.9192 | 0.9207 | 0.9222 | 0.9236 | 0.9251 | 0.9265 | 0.9279 | 0.9292 | 0.9306 | 0.9319 |
| 1.5 | 0.9332 | 0.9345 | 0.9357 | 0.9370 | 0.9382 | 0.9394 | 0.9406 | 0.9418 | 0.9429 | 0.9441 |
| 1.6 | 0.9452 | 0.9463 | 0.9474 | 0.9484 | 0.9495 | 0.9505 | 0.9515 | 0.9525 | 0.9535 | 0.9545 |
| 1.7 | 0.9554 | 0.9564 | 0.9573 | 0.9582 | 0.9591 | 0.9599 | 0.9608 | 0.9616 | 0.9625 | 0.9633 |
| 1.8 | 0.9641 | 0.9649 | 0.9656 | 0.9664 | 0.9671 | 0.9678 | 0.9686 | 0.9693 | 0.9699 | 0.9706 |
| 1.9 | 0.9713 | 0.9719 | 0.9726 | 0.9732 | 0.9738 | 0.9744 | 0.9750 | 0.9756 | 0.9761 | 0.9767 |
| 2.0 | 0.9772 | 0.9778 | 0.9783 | 0.9788 | 0.9793 | 0.9798 | 0.9803 | 0.9808 | 0.9812 | 0.9817 |
| 2.1 | 0.9821 | 0.9826 | 0.9830 | 0.9834 | 0.9838 | 0.9842 | 0.9846 | 0.9850 | 0.9854 | 0.9857 |
| 2.2 | 0.9861 | 0.9864 | 0.9868 | 0.9871 | 0.9875 | 0.9878 | 0.9881 | 0.9884 | 0.9887 | 0.9890 |
| 2.3 | 0.9893 | 0.9896 | 0.9898 | 0.9901 | 0.9904 | 0.9906 | 0.9909 | 0.9911 | 0.9913 | 0.9916 |
| 2.4 | 0.9918 | 0.9920 | 0.9922 | 0.9925 | 0.9927 | 0.9929 | 0.9931 | 0.9932 | 0.9934 | 0.9936 |
| 2.5 | 0.9938 | 0.9940 | 0.9941 | 0.9943 | 0.9945 | 0.9946 | 0.9948 | 0.9949 | 0.9951 | 0.9952 |
| 2.6 | 0.9953 | 0.9955 | 0.9956 | 0.9957 | 0.9959 | 0.9960 | 0.9961 | 0.9962 | 0.9963 | 0.9964 |
| 2.7 | 0.9965 | 0.9966 | 0.9967 | 0.9968 | 0.9969 | 0.9970 | 0.9971 | 0.9972 | 0.9973 | 0.9974 |
| 2.8 | 0.9974 | 0.9975 | 0.9976 | 0.9977 | 0.9977 | 0.9978 | 0.9979 | 0.9979 | 0.9980 | 0.9981 |
| 2.9 | 0.9981 | 0.9982 | 0.9982 | 0.9983 | 0.9984 | 0.9984 | 0.9985 | 0.9985 | 0.9986 | 0.9986 |
| 3.0 | 0.9987 | 0.9987 | 0.9987 | 0.9988 | 0.9988 | 0.9989 | 0.9989 | 0.9989 | 0.9990 | 0.9990 |