Interest Rates

Options and Futures
Lorenzo Naranjo

Spring 2024

Introduction

Interest Rates and Derivatives

  • The pricing of financial assets is always relative to some benchmarks that we believe are well priced.
  • In order to compare cash flows occurring at different points in time, we use risk-free bonds as the relevant benchmarks.
  • Unfortunately, real financial markets are rarely fully integrated, so the landscape of interest rates is varied and complex.
  • Moreover, when pricing options and other derivatives, it is common both by academics and practitioners to use continuous compounding to discount riskless cash flows.

Example 1

  • Consider a zero-coupon bond that pays for certain $100 in 2 years.
  • The bond today costs $95.

  • The fact that $100 paid in two years costs today $95 can also be expressed as a percentage rate of return per year. \[ 95 (1 + r)^{2} = 100 \Rightarrow r = \left( \frac{100}{95} \right)^{1/2} - 1 = 2.60\%. \]
  • In other words, the implicit interest rate paid by the 2-year zero coupon bond is 2.60% per year compounded annually.

Example 1 (continued)

  • This means that every dollar paid for certain in two years today costs $0.95.

  • Thus, a bond that pays for certain $50,000 in two years today should cost \(0.95 \times 50{,}000 = \$47{,}500.\)

An Arbitrage Example

  • What if this new bond trades for a different price, say $47,000?
  • Then there would be an arbitrage opportunity.
  • These two strategies pay the same:
    • 500 bonds paying $100 in two years
    • 1 bond paying $50,000 in two years
  • How to profit?
    • Buy the bond with face value $50,000 expiring in two years.
    • Sell 500 bonds with face value $100 expiring at the same date.
  • This long-short strategy provides today with a positive cash-flow of $500 and is fully hedged in two years.

Different Types of Interest Rates

Treasury Rates

  • The United States government through the Department of the Treasury issues Bills, Notes and Bonds to finance government activities.
  • Treasury bonds are usually perceived as risk-free, i.e. no risk of default.
  • Despite the size of the U.S. Treasury market, the demand for Treasury securities often surpasses its supply.
  • For this reason, the yield-to-maturity (YTM) of Treasury bonds might be lower than the rate of a fully collateralized loan.
  • Therefore, Treasury rates are commonly not used as benchmark rates to price derivative securities.

U.S. Public Debt

LIBOR

  • The London Interbank Offered Rate (LIBOR) has been at the heart of the financial system for many decades.
  • For all this time, LIBOR has provided a reference for pricing derivatives, loans and securities.
  • Large corporate loans used to be indexed to LIBOR.
  • Since many borrowers liked to pay a fixed rate, one of the most important derivatives that used LIBOR as a reference rate were interest rate swaps.
  • LIBOR is no longer used and in the U.S. it has been replaced with SOFR.

OIS and Overnight Rates

  • In the United States, banks are required to maintain reserves in cash with the Federal Reserve.
  • When a bank needs to increase their reserves, they usually borrow overnight from another bank that might have a reserve surplus.
  • The weighted-average rate of these brokered transactions is termed the (EFFR).
  • When the Federal Reserve determines the , they implement their policy by making sure that the EFFR is close every day to their target.
  • An overnight indexed swap (OIS) is an over-the-counter financial contract in which one party pays the compounded EFFR over a certain period, say three months, in exchange for a fixed payment.

Evolution of the Effective Federal Funds Rate

Federal Reserve Interest Rate Policy

SOFR and Repo Rates

  • A repurchase agreement or repo, a financial institution or trader sells some securities to a counterparty with the agreement to repurchase them back later for a slightly higher price.
  • The implicit interest rate in this transaction is the repo rate.
  • Unlike LIBOR and the EFFR, repo rates are secured borrowing rates.
  • The weighted average of these repo transactions is called the (SOFR).
  • Effective 2022, this rate has replaced LIBOR USD.

Federal Reserve Interest Rate Policy

Compounding Frequencies

Compounding Multiple Times per Year

  • Suppose you have $100 to invest for a year and the interest rate is 10%.
  • It makes a difference how often you compound the interest.
  • As you compound more often you earn more interest-on-interest.
Compounding Frequency Future Value
Annual \(100(1.10)=\$110.00\)
Semi-Annual \(100(1.05)^{2}=\$110.25\)
Quarterly \(100\left(1+\frac{0.10}{4}\right)^{4}=\$110.38\)
Monthly \(100\left(1+\frac{0.10}{12}\right)^{12}=\$110.47\)
Daily \(100\left(1+\frac{0.10}{365}\right)^{365}=\$110.52\)

Compounding in the Limit

  • It turns out that there is a limit to the compounding operation we just did: \[ \lim_{n\rightarrow\infty} 100\left(1+\frac{0.10}{n}\right)^{n} = 100e^{0.10} = \$110.52. \]
  • We call this operation continuous compounding, and you can see that compounding daily is already a pretty good approximation of it.
  • In general, if we denote by \(r\) the continuously-compounded interest rate, the relationship between present value (PV) and future value (FV) is given by: \[ \text{FV}=\text{PV}e^{rT} \Longleftrightarrow \text{PV}=\text{FV}e^{-rT} \]

A Note on Exponentials

  • In the previous expression \(e^{x} = \exp(x)\) is called the exponential function.
  • In a spreadsheet, for example, if you want to compute \(100 e^{0.10}\) you need to type =100*exp(0.10), which will return 110.52.
  • If, on the other hand, you want to know which rate \(r\) gives you a future value of $110 over a year if you invest $100 and the rate is compounded continuosly, then we need to solve: \[ 110 = 100 e^{r}, \] which is the same as solving for \(r\) in \(e^{r} = 1.10.\)
  • The natural logarithm function allows us to solve for \(r,\) that is \[ e^{r} = 1.10 \Leftrightarrow r = \ln(1.10) = 9.53\%. \]

Effective Annual Rate (EAR)

  • In the previous slide we saw that \[ 100 \times 1.10 = 110 = 100e^{0.0953}. \]
  • Therefore 10% per year compounded annually is the same as 9.53% per year compounded continuously because it gives us the same amount of money after a year.
  • We can also say that 9.53% per year compounded continuously is equivalent to an effective annual rate (EAR) of 10% per year.

Example 2: Pricing a Zero-Coupon Bond

  • A zero-coupon bond pays its principal or face-value (FV) at maturity but makes no intermediate payments.

  • The continuously-compounded interest rate is 8% per year.
  • Consider a zero-coupon risk-free bond with face value $1,000 and expiring in seven months.
  • The price of the bond is: \[ B = 1000e^{-0.08 \times 7/12} = \$954.41. \]

Example 3: Pricing a Coupon-Bond

  • A coupon-bond pays a periodic amount (C) either every year or every six months, and its principal or face-value (FV) at maturity.

  • The continuously-compounded interest rate is 6% per year.
  • Consider a bond that pays coupons of 4% every year over a notional of $1,000 and expiring in four years.
  • The price of the bond is: \[ B = 40e^{-0.06 \times 1} + 40e^{-0.06 \times 2} + 40e^{-0.06 \times 3} + 1040e^{-0.06 \times 4} = \$924.65. \]

Zero Rates

Where Do Zero Rates Come From?

  • In general, the interest rate for different maturities is not the same.
  • The collection of interest rates for different maturities is called the term-structure of interest rates.
  • The price of a zero-coupon bond is determined by discounting its face-value at the relevant interest rate.
  • For a given maturity \(\tau,\) the \(\tau\)-year zero rate, denoted by \(r(\tau),\) is the interest rate that gives the correct \(\tau\)-year zero-coupon bond price \(Z_{\tau}\).
  • If \(r(\tau)\) is a continuously-compounded rate we must have: \[ Z_{\tau} = F e^{-r(\tau) \tau}. \]

Example 4

  • You have the following information for zero rates expressed per year with continuous compounding.
Maturity (months) 1 3 6 9 12
Zero Rate (%) 6.0 6.4 6.6 6.8 7.0
  • Consider a zero-coupon risk-free bond with face value $1,000 and expiring in 9 months.
  • The price of the bond is: \[ B = 1000e^{-0.068 \times 9/12} = \$950.28. \]