Interest Rates
Options, Futures and Derivative Securities
Spring 2025
Interest Rates and Derivatives
- The pricing of financial assets is always relative to some benchmarks that we believe are well priced.
- In order to compare cash flows occurring at different points in time, we use risk-free bonds as the relevant benchmarks.
- Unfortunately, real financial markets are rarely fully integrated, so the landscape of interest rates is varied and complex.
- Moreover, when pricing options and other derivatives, it is common both by academics and practitioners to use continuous compounding to discount riskless cash flows.
Example 1
- Consider a zero-coupon bond that pays for certain $100 in 2 years.
- The bond today costs $95.
- The fact that $100 paid in two years costs today $95 can also be expressed as a percentage rate of return per year.
95 (1 + r)^{2} = 100 \Rightarrow r = \left( \frac{100}{95} \right)^{1/2} - 1 = 2.60\%.
- In other words, the implicit interest rate paid by the 2-year zero coupon bond is 2.60% per year compounded annually.
Example 1 (continued)
- This means that every dollar paid for certain in two years today costs $0.95.
- Thus, a bond that pays for certain $50,000 in two years today should cost 0.95 \times 50{,}000 = \$47{,}500.
An Arbitrage Example
- What if this new bond trades for a different price, say $47,000?
- Then there would be an arbitrage opportunity.
- These two strategies pay the same:
- 500 bonds paying $100 in two years
- 1 bond paying $50,000 in two years
- How to profit?
- Buy the bond with face value $50,000 expiring in two years.
- Sell 500 bonds with face value $100 expiring at the same date.
- This long-short strategy provides today with a positive cash-flow of $500 and is fully hedged in two years.
Different Types of Interest Rates
Treasury Rates
- The United States government through the Department of the Treasury issues Bills, Notes and Bonds to finance government activities.
- Treasury bonds are usually perceived as risk-free, i.e. no risk of default.
- Despite the size of the U.S. Treasury market, the demand for Treasury securities often surpasses its supply.
- For this reason, the yield-to-maturity (YTM) of Treasury bonds might be lower than the rate of a fully collateralized loan.
- Therefore, Treasury rates are commonly not used as benchmark rates to price derivative securities.
U.S. Public Debt
LIBOR
- The London Interbank Offered Rate (LIBOR) has been at the heart of the financial system for many decades.
- For all this time, LIBOR has provided a reference for pricing derivatives, loans and securities.
- Large corporate loans used to be indexed to LIBOR.
- Since many borrowers liked to pay a fixed rate, one of the most important derivatives that used LIBOR as a reference rate were interest rate swaps.
- LIBOR is no longer used and in the U.S. it has been replaced with SOFR.
OIS and Overnight Rates
- In the United States, banks are required to maintain reserves in cash with the Federal Reserve.
- When a bank needs to increase their reserves, they usually borrow overnight from another bank that might have a reserve surplus.
- The weighted-average rate of these brokered transactions is termed the (EFFR).
- When the Federal Reserve determines the , they implement their policy by making sure that the EFFR is close every day to their target.
- An overnight indexed swap (OIS) is an over-the-counter financial contract in which one party pays the compounded EFFR over a certain period, say three months, in exchange for a fixed payment.
Evolution of the Effective Federal Funds Rate
Federal Reserve Interest Rate Policy
SOFR and Repo Rates
- A repurchase agreement or repo, a financial institution or trader sells some securities to a counterparty with the agreement to repurchase them back later for a slightly higher price.
- The implicit interest rate in this transaction is the repo rate.
- Unlike LIBOR and the EFFR, repo rates are secured borrowing rates.
- The weighted average of these repo transactions is called the (SOFR).
- Effective 2022, this rate has replaced LIBOR USD.
Federal Reserve Interest Rate Policy
Compounding Multiple Times per Year
- Suppose you have $100 to invest for a year and the interest rate is 10%.
- It makes a difference how often you compound the interest.
- As you compound more often you earn more interest-on-interest.
Annual |
100(1.10)=\$110.00 |
Semi-Annual |
100(1.05)^{2}=\$110.25 |
Quarterly |
100\left(1+\frac{0.10}{4}\right)^{4}=\$110.38 |
Monthly |
100\left(1+\frac{0.10}{12}\right)^{12}=\$110.47 |
Daily |
100\left(1+\frac{0.10}{365}\right)^{365}=\$110.52 |
Compounding in the Limit
- It turns out that there is a limit to the compounding operation we just did:
\lim_{n\rightarrow\infty} 100\left(1+\frac{0.10}{n}\right)^{n} = 100e^{0.10} = \$110.52.
- We call this operation continuous compounding, and you can see that compounding daily is already a pretty good approximation of it.
- In general, if we denote by r the continuously-compounded interest rate, the relationship between present value (PV) and future value (FV) is given by:
\text{FV}=\text{PV}e^{rT} \Longleftrightarrow \text{PV}=\text{FV}e^{-rT}
A Note on Exponentials
- In the previous expression e^{x} = \exp(x) is called the exponential function.
- In a spreadsheet, for example, if you want to compute 100 e^{0.10} you need to type
=100*exp(0.10)
, which will return 110.52
.
- If, on the other hand, you want to know which rate r gives you a future value of $110 over a year if you invest $100 and the rate is compounded continuosly, then we need to solve:
110 = 100 e^{r},
which is the same as solving for r in e^{r} = 1.10.
- The natural logarithm function allows us to solve for r, that is
e^{r} = 1.10 \Leftrightarrow r = \ln(1.10) = 9.53\%.
Effective Annual Rate (EAR)
- In the previous slide we saw that
100 \times 1.10 = 110 = 100e^{0.0953}.
- Therefore 10% per year compounded annually is the same as 9.53% per year compounded continuously because it gives us the same amount of money after a year.
- We can also say that 9.53% per year compounded continuously is equivalent to an effective annual rate (EAR) of 10% per year.
Example 2: Pricing a Zero-Coupon Bond
- A zero-coupon bond pays its principal or face-value (FV) at maturity but makes no intermediate payments.
- The continuously-compounded interest rate is 8% per year.
- Consider a zero-coupon risk-free bond with face value $1,000 and expiring in seven months.
- The price of the bond is:
B = 1000e^{-0.08 \times 7/12} = \$954.41.
Example 3: Pricing a Coupon-Bond
- A coupon-bond pays a periodic amount (C) either every year or every six months, and its principal or face-value (FV) at maturity.
- The continuously-compounded interest rate is 6% per year.
- Consider a bond that pays coupons of 4% every year over a notional of $1,000 and expiring in four years.
- The price of the bond is:
B = 40e^{-0.06 \times 1} + 40e^{-0.06 \times 2} + 40e^{-0.06 \times 3} + 1040e^{-0.06 \times 4} = \$924.65.
Where Do Zero Rates Come From?
- In general, the interest rate for different maturities is not the same.
- The collection of interest rates for different maturities is called the term-structure of interest rates.
- The price of a zero-coupon bond is determined by discounting its face-value at the relevant interest rate.
- For a given maturity \tau, the \tau-year zero rate, denoted by r(\tau), is the interest rate that gives the correct \tau-year zero-coupon bond price Z_{\tau}.
- If r(\tau) is a continuously-compounded rate we must have:
Z_{\tau} = F e^{-r(\tau) \tau}.
Example 4
- You have the following information for zero rates expressed per year with continuous compounding.
Zero Rate (%) |
6.0 |
6.4 |
6.6 |
6.8 |
7.0 |
- Consider a zero-coupon risk-free bond with face value $1,000 and expiring in 9 months.
- The price of the bond is:
B = 1000e^{-0.068 \times 9/12} = \$950.28.